JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Self Evaluation Test - Laws of Motion

  • question_answer
    In the diagram shown, friction is completely absent. If a force F has been applied on the wedge such that it moves with a constant velocity than value of normal reaction N' is

    A) \[>F\]

    B) \[<F\]

    C) \[=F\]

    D) cannot find

    Correct Answer: A

    Solution :

    [a] For the wedge, \[{{N}^{A}}\sin \theta =F\] \[\therefore {{N}^{A}}=\frac{F}{\sin \theta }.\text{ As sin}\theta \text{1, and so N }\!\!'\!\!\text{ F}\]


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