JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Self Evaluation Test - Laws of Motion

  • question_answer
    The acceleration of the system shown in the figure is given by the expression (coefficient of friction between m, and surface is \[\mu \])            

    A) \[a=\frac{\left( {{m}_{2}}-\mu {{m}_{1}} \right)}{\left( {{m}_{1}}+{{m}_{2}} \right)}\]

    B) \[a=\frac{{{m}_{1}}g}{\left( {{m}_{1}}+{{m}_{2}} \right)}\]

    C) \[a=\frac{\left( {{m}_{1}}+\mu {{m}_{2}} \right)}{\left( {{m}_{1}}+{{m}_{2}} \right)g}\]

    D)        \[a=\frac{\left( {{m}_{1}}-{{m}_{2}} \right)\mu }{\left( {{m}_{1}}+{{m}_{2}} \right)g}\]

    Correct Answer: A


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