A) \[4:3\]
B) \[5:4\]
C) \[1:4\]
D) \[3:2\]
Correct Answer: C
Solution :
[c] Tension at the highest point \[{{T}_{top}}=\frac{m{{v}^{2}}}{r}-mg=2mg\left( \therefore {{v}_{top}}=\sqrt{3gr} \right)\] Tension at the lowest point \[{{T}_{bottom}}=2mg+6mg=8mg\] \[\therefore \frac{{{T}_{top}}}{{{T}_{bottom}}}=\frac{2mg}{8mg}=\frac{1}{4}.\]You need to login to perform this action.
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