A) 100 N
B) 50 N
C) 240 N
D) 180 N
Correct Answer: C
Solution :
[c] As m would slip in vertically downward direction, then \[mg=\mu N\] \[\Rightarrow \,\,N=\frac{mg}{\mu }=\frac{100}{0.5}=200\,\,\operatorname{Newton}\] Same normal force would accelerated M, \[\operatorname{thus}\,\,{{a}_{M}}=\frac{200}{50}=4m/{{s}^{2}}\] Taking \[m+M\]as system \[F=(m+M)4=240\,N\]
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