A) \[2mv\sin \frac{\pi }{n}\]
B) \[mv\sin \frac{\pi }{n}\]
C) \[mv\sin \frac{n}{\pi }\]
D) \[mv\sin \frac{n}{\pi }\]
Correct Answer: A
Solution :
[a] \[\vec{j}=m\left( {{{\vec{v}}}_{f}}-{{{\vec{v}}}_{i}} \right)\] \[=2mv\sin \theta /2=2mv\sin \pi /n.\]You need to login to perform this action.
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