JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Self Evaluation Test - Laws of Motion

  • question_answer
    A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A bob is suspended from the roof of the car by a light wire of length 1.0 m. The angle made by the wire with the vertical is

    A) \[0{}^\circ \]  

    B) \[\frac{\pi }{3}\]

    C) \[\frac{\pi }{6}\]  

    D) \[\frac{\pi }{4}\]

    Correct Answer: D

    Solution :

    [d] Given; \[speed=10\text{ }m/s;\]radius \[r=10\text{ }m\]Angle made by the wire with the vertical \[\tan \,\theta =\frac{{{v}^{2}}}{rg}=\frac{{{10}^{2}}}{10\times 10}=1\Rightarrow \theta ={{45}^{o}}=\frac{\pi }{4}\]


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