JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Self Evaluation Test - Laws of Motion

  • question_answer
    A particle is moving along a circular path in the xy plane (see figure). When it crosses the x-axis, it has an acceleration along the path of\[1.5\text{ }m/{{s}^{2}}\], and is moving with a speed of 10 m/s in the negatives-direction. The total acceleration of the particle is:      

    A) \[50\hat{i}-1.5\hat{j}\text{ m/}{{\text{s}}^{2}}\]

    B) \[-50\hat{i}-1.5\hat{j}\text{ m/}{{\text{s}}^{2}}\]

    C) \[10\hat{i}-1.5\hat{j}\text{ m/}{{\text{s}}^{2}}\]

    D) \[1.5\hat{i}-50\hat{j}\text{ m/}{{\text{s}}^{2}}\]

    Correct Answer: B

    Solution :

    [b] Centripetal acceleration \[{{a}_{n}}=\frac{{{v}^{2}}}{r}=\frac{{{10}^{2}}}{2}=50m/{{s}^{2}}\], along negative x-axis. so           \[\overrightarrow{a}=-50\hat{i}-1.5\hat{j}m/{{s}^{2}}\]


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