A) Equal to 1
B) Equal to 0
C) Does not exist
D) None of these
Correct Answer: B
Solution :
[b] L.H.L \[=\underset{x\to 0-}{\mathop{\lim }}\,f(x)=\underset{h\to 0}{\mathop{\lim }}\,\frac{\sin [cosh]}{1+[cosh]}=\frac{\sin (0)}{1+0}=0\] \[(\therefore h>0\Rightarrow cosh<1)\] R.H.L. \[=\underset{x\to 0+}{\mathop{\lim }}\,f(x)=\underset{h\to 0}{\mathop{\lim }}\,\frac{\sin [cosh]}{1+[cosh]}=\frac{\sin (0)}{1+0}=0\]
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