A) \[{{x}^{2}}-6x+9=0\]
B) \[{{x}^{2}}-10x+21=0\]
C) \[{{x}^{2}}-14x+49=0\]
D) None of these
Correct Answer: B
Solution :
[b] \[\underset{x\to 2-0}{\mathop{\lim }}\,f(x)=\underset{x\to 2-0}{\mathop{\lim }}\,({{x}^{2}}-1)={{2}^{2}}-1=3\] \[\underset{x\to 2+0}{\mathop{\lim }}\,f(x)=\underset{x\to 2+0}{\mathop{\lim }}\,(2x+3)=2\times 2+3=7\] \[\therefore \] Required quadratic equation is \[{{x}^{2}}-10x+21=0\]
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