A) \[-1\]
B) \[2\]
C) \[\sqrt{5}\]
D) \[3\]
Correct Answer: B
Solution :
[b] \[{{x}_{n+1}}=\sqrt{2+{{x}_{n}}}\Rightarrow \lim {{x}_{n+1}}=\sqrt{2+\lim {{x}_{n}}}\] \[\Rightarrow t=\sqrt{2+t}\] \[[\because \lim {{x}_{n+1}}=lim{{x}_{n}}]\] \[\Rightarrow {{t}^{2}}-t-2=0\Rightarrow (t-2)(t+1)=0\Rightarrow t=2.\]You need to login to perform this action.
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