A) 1
B) Does not exist
C) 0
D) None of these
Correct Answer: A
Solution :
[a] \[\underset{x\to {{0}^{+}}}{\mathop{\lim }}\,=\underset{x\to {{0}^{+}}}{\mathop{\lim }}\,{{(x)}^{0}}=1,\] \[\underset{x\to {{0}^{-}}}{\mathop{\lim }}\,{{(-x)}^{0}}=\underset{x\to {{0}^{-}}}{\mathop{\lim }}\,1=1\]
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