A) Does not exist
B) 2
C) 0
D) -1
Correct Answer: C
Solution :
[c] \[\because [1/x]=integer\] \[\therefore {{(-1)}^{[1/x]}}=1or-1\] \[\underset{x\to 0}{\mathop{\lim }}\,x{{(-1)}^{[1/x]}}=\underset{h\to 0}{\mathop{\lim }}\,(h)(1or-1)=0\] \[=\underset{h\to 0}{\mathop{\lim }}\,(-h)\,(1or-1)=0\]
You need to login to perform this action.
You will be redirected in
3 sec
