A) 5
B) 6
C) 7
D) Does not exist
Correct Answer: B
Solution :
[b] min \[({{y}^{2}}-4y+11)=min[{{(y-2)}^{2}}+7]=7\] or \[L=\underset{x\to 0}{\mathop{\lim }}\,\left[ \min ({{y}^{2}}-4y+11)\frac{\sin x}{x} \right]\] \[=\underset{x\to 0}{\mathop{\lim }}\,\left[ \frac{7\sin x}{x} \right]\] = [a value slightly lesser than 7] \[(\left| \sin x \right|<\left| x \right|,when\,\,\,x\to 0)\] \[=\underset{x\to 0}{\mathop{\lim }}\,\left[ 7\frac{\sin x}{x} \right]=6.\]
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