A) \[(2,4)\]
B) \[(-5,-4]\cup (2,3]\]
C) \[[-4,-3)\cup [3,4)\]
D) None of these
Correct Answer: B
Solution :
[b] \[{{(x)}^{2}}+{{(x+1)}^{2}}=25\Rightarrow {{(x)}^{2}}+{{\{(x)+1\}}^{2}}=25\] \[\Rightarrow 2{{(x)}^{2}}+2(x)-24=0\] \[\Rightarrow {{(x)}^{2}}+(x)-12=0\Rightarrow (x)=-4or3\] Now \[(x)=-4\Rightarrow -5<x\le -4\]and \[(x)=3\Rightarrow 2<x\le 3\] \[\therefore \] Solution set is \[(-5,\,\,-\,4]\cup (2,\,\,3]\]
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