A) 2
B) 3
C) 4
D) 5
Correct Answer: A
Solution :
[a] \[\frac{2x-1}{3}\ge \frac{15x-10-8+4x}{20}\] \[\Rightarrow \,\,\,\,\,\frac{2x-1}{3}\ge \frac{19x-18}{20}\] \[\Rightarrow 40x-20\ge 57x-54\Rightarrow -17x\ge -34\Rightarrow x\le 2\] \[\Rightarrow \,\,\,x\in (-\infty ,\,\,2]\]You need to login to perform this action.
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