A) \[(-2,-1)\]
B) \[(-2,3)\]
C) \[(-1,3)\]
D) \[(3,\infty )\]
Correct Answer: B
Solution :
[b] \[(x+2)(x+4)>0.x+2>0\Rightarrow x>-2.\] Now (1) can be written as \[{{\log }_{3}}(x+2)(x+4)-lo{{g}_{3}}(x+2)<\frac{(log7)/2}{(log3)/2}\] \[\Rightarrow {{\log }_{3}}(x+4)<lo{{g}_{3}}^{7}\Rightarrow x+4<7\,\,or\,\,x<3.\]You need to login to perform this action.
You will be redirected in
3 sec