A) More than 120 liters but less than 300 liters
B) More than 140 liters but less than 600 liters
C) More than 100 liters but less than 280 liters
D) More than 160 liters but less than 500 liters
Correct Answer: A
Solution :
[a] Let x liters of 30% acid solution is required to be added. Then, |
\[Total\text{ }mixture=(x+600)\,\,liters\] |
\[\therefore \] 30% of x + 12% of 600>15% of (x + 600) |
and 30% of x + 12% of 600<18% of (x + 600) |
or \[\frac{30x}{100}+\frac{12}{100}(600)>\frac{15}{100}(x+600)\] |
And \[\frac{30x}{100}+\frac{12}{100}(600)<\frac{18}{100}(x+600)\] |
or \[30x+7200>15x+9000\] and |
\[30x+7200<18x+10800\] |
or \[15x>1800\] and \[12x<3600\] or \[x>120\] and \[x<300\] |
i.e., \[120<x<300\] |
Thus, the number of liters of the 30% solution of acid will have to be more than 120 liters but less than 300 liters. |
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