2. Questions Bank
  3. JEE Main & Advanced
  4. Mathematics
  5. Equations and Inequalities

JEE Main & Advanced Mathematics Equations and Inequalities Question Bank Self Evaluation Test - Linear Inequalities

  • question_answer
    Set of values of x satisfying the inequality \[\frac{{{x}^{2}}+6x-7}{\left| x+4 \right|}<0\] is/are

    A) \[(-\infty ,-7)\]

    B) \[(-7,4)\]

    C) \[(-4,1)\]

    D) \[(1,\infty )\]

    Correct Answer: C

    Solution :

    [c] \[\frac{{{x}^{2}}+6x-7}{\left| x+4 \right|}<0\] \[\Rightarrow {{x}^{2}}+6x-7<0,\] provided \[x+4\ne 0\]                         \[[\because \,\,\,\,\left| x+4 \right|>\,0\,\,if\,\,x\ne -\,4]\] \[\Rightarrow (x+7)(x-1)<0,x\ne -4\Rightarrow -7<x<1,\]\[x\ne -4\] \[\therefore x\in (-7,-4)\cup (-4,1)\]


You need to login to perform this action.
You will be redirected in 3 sec spinner