question_answer

In equations \[3x-y\ge 3\] and \[4x-y\ge 4\]

A) Have solution for positive x and y

B) Have no solution for positive x and y

C) Have solution for all x

D) Have solution for all y  

Correct Answer: A

Solution :

[a] Following figure will be obtained on drawing the graphs of given in equations. From \[3x-y\ge 3,\] \[\Rightarrow \frac{x}{1}+\frac{y}{-3}=1\] From \[4x-y\ge 4,\] \[\Rightarrow \frac{x}{1}+\frac{y}{-4}=1\] Clearly the common region of both is true for positive value of (x, y).