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JEE Main & Advanced Mathematics Linear Programming Question Bank Self Evaluation Test - Linear Programming

  • question_answer
    The true statement for the graph of in equations\[3x+2y\le 6\] and \[6x+4y\ge 20,\] is

    A) Both graph are disjoint

    B) Both contain (0, 3)

    C) Both contain point (1, 1)

    D) None of these

    Correct Answer: A

    Solution :

    [a] The equations, corresponding to inequalities \[3x+2y\le 6\] and \[6x+4y\ge 20,\] are \[3x+2y=6\]and\[6x+4y=20\], so the lines represented by these equation are parallel. Hence the graphs are disjoint.


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