A) \[\frac{2}{\sqrt{3}}{{\left( \frac{\tau }{B.i} \right)}^{\frac{1}{2}}}\]
B) \[2{{\left( \frac{\tau }{\sqrt{3}B.i} \right)}^{\frac{1}{2}}}\]
C) \[\frac{2}{\sqrt{3}}\left( \frac{\tau }{B.i} \right)\]
D) \[\frac{1}{\sqrt{3}}\frac{\tau }{B.i}\]
Correct Answer: B
Solution :
[b] \[\tau =MB\,\sin \,\theta ,\,\tau =iAB\,\sin \,{{90}^{o}}\] \[\therefore \,\,\,\,A=\frac{\tau }{iB}=1/2(BC)(AD)\]You need to login to perform this action.
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