A) \[2\times {{10}^{-3}}N\]
B) \[2\times {{10}^{-4}}N\]
C) \[2\times {{10}^{5}}N\]
D) \[2\times {{10}^{-5}}N\]
Correct Answer: A
Solution :
[a] \[F=\frac{{{\mu }_{0}}}{4\pi }\frac{{{m}_{1}}{{m}_{2}}}{{{r}^{2}}}={{10}^{-7}}\times \frac{30\times 60}{{{(0.3)}^{2}}}=2\times {{10}^{-3}}\,N\]
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