A) 1 : 3
B) 1 : 1
C) 3 : 1
D) 9 : 1
Correct Answer: C
Solution :
[c] \[{{T}_{1}}=2\pi \sqrt{\frac{I}{HM}}\], and \[{{T}_{2}}=2\pi \sqrt{\frac{I}{(H+F)M}}\] \[\frac{T_{1}^{2}}{T_{2}^{2}}=\frac{H+F}{H}=\frac{{{T}^{2}}}{{{T}^{2}}/4}=\frac{4}{1}\Rightarrow H+F=4H\] \[\Rightarrow \,\,3H=F\]You need to login to perform this action.
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