A) \[\chi \]
B) \[0.5\chi \]
C) \[2\chi \]
D) \[11.1\chi \]
Correct Answer: B
Solution :
[b] \[\frac{{{\chi }_{{{m}_{1}}}}}{{{\chi }_{{{m}_{2}}}}}=\frac{{{T}_{2}}}{{{T}_{1}}}=\frac{273+333}{273+30}=\frac{606}{303}=2\] \[\therefore \,\,\,\,{{\chi }_{{{m}_{2}}}}={{\chi }_{{{m}_{1}}}}/2=0.5{{\chi }_{{{m}_{1}}}}=0.5\chi .(\because \,{{\chi }_{{{m}_{1}}}}=\chi )\]You need to login to perform this action.
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