A) \[7.2\times {{10}^{5}}\,A\,{{m}^{-1}}\]
B) \[7.2\times {{10}^{3}}\,A\,{{m}^{-1}}\]
C) \[7.2\times {{10}^{9}}\,A\,{{m}^{-1}}\]
D) \[7.2\times {{10}^{12}}\,A\,{{m}^{-1}}\]
Correct Answer: A
Solution :
[a] The volume of the cube is \[V={{({{10}^{-6}}\,m)}^{3}}={{10}^{-18}}\,{{m}^{3}}\] Net dipole moment \[{{m}_{net}}\] \[=8\times {{10}^{10}}\times 9\times {{10}^{-24}}\,A{{m}^{2}}\] \[=72\times {{10}^{-14}}\,A\,{{m}^{2}}\] Intensity of magnetization is magnetic moment developed per unit volume. \[\therefore \,\,\,\] magnetization, \[M=\frac{{{m}_{net}}}{volume}\] \[=\frac{72\times {{10}^{-14}}\,A\,{{m}^{2}}}{{{10}^{-18}}\,{{m}^{3}}}=7.2\times {{10}^{5}}\,A\,{{m}^{-1}}\]You need to login to perform this action.
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