JEE Main & Advanced Physics Magnetism Question Bank Self Evaluation Test - Magnetism and Matter

  • question_answer
    A compass needle placed at a distance r from a short magnet in Tan A position shows a deflection of \[60{}^\circ \]. If the distance is increased to r \[{{(3)}^{1/3}}\], then deflection of compass needle is

    A) \[{{30}^{o}}\]

    B) \[60\times {{3}^{\frac{1}{3}}}\]

    C) \[60\times {{3}^{\frac{2}{3}}}\]

    D) \[60\times {{3}^{\frac{3}{3}}}\]

    Correct Answer: A

    Solution :

    [a] \[\frac{\tan \,{{\theta }_{2}}}{\tan \,{{\theta }_{1}}}=\frac{d_{1}^{3}}{d_{2}^{3}}=\frac{{{r}^{3}}}{{{[r{{(3)}^{1/3}}]}^{3}}}=\frac{1}{3}\] \[\tan \,{{\theta }_{2}}=\frac{1}{3}\tan \,{{\theta }_{1}}=\frac{\tan 60}{3}=\frac{\sqrt{3}}{3}=\frac{1}{\sqrt{3}}\] \[\therefore \,\,\,\,\,{{\theta }_{2}}=30{}^\circ \]


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