A) 14.6
B) 19.4
C) 9.7
D) 4.9
Correct Answer: C
Solution :
[c] Here, \[r=30cm=0.3cm\] we know \[\frac{{{\mu }_{0}}M}{4\pi {{r}^{3}}}={{B}_{H}}=3.6\times {{10}^{-5}}\] \[\Rightarrow \,\,\,M=\frac{3.6\times {{10}^{-5}}}{{{10}^{-7}}}{{(0.3)}^{3}}=9.7\,A{{m}^{2}}\]You need to login to perform this action.
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