A) \[\frac{{{T}_{0}}}{2}\]
B) \[\frac{{{T}_{0}}}{\sqrt{2}}\]
C) \[\sqrt{2}{{T}_{0}}\]
D) \[2{{T}_{0}}\]
Correct Answer: C
Solution :
[c] \[{{I}_{1}}=\frac{m{{\ell }^{2}}}{12}\] and \[{{I}_{2}}=\frac{(2m){{\ell }^{2}}}{12}=2{{I}_{1}}\]. Now, \[\frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{{{I}_{1}}}{{{I}_{2}}}}\] or \[\frac{{{T}_{0}}}{{{T}_{2}}}=\sqrt{\frac{1}{2}}\] \[\therefore \,\,\,\,{{T}_{2}}=\sqrt{2}\,{{T}_{0}}\]You need to login to perform this action.
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