JEE Main & Advanced Physics Magnetism Question Bank Self Evaluation Test - Magnetism and Matter

  • question_answer
    The time period of oscillation of a bar magnet suspended horizontally along the magnetic meridian is \[{{T}_{0}}\]. If this magnet is replaced by another magnet of the same size and pole strength but with double the mass, the new time period will be

    A) \[\frac{{{T}_{0}}}{2}\]  

    B) \[\frac{{{T}_{0}}}{\sqrt{2}}\]  

    C) \[\sqrt{2}{{T}_{0}}\]

    D) \[2{{T}_{0}}\]

    Correct Answer: C

    Solution :

    [c] \[{{I}_{1}}=\frac{m{{\ell }^{2}}}{12}\] and \[{{I}_{2}}=\frac{(2m){{\ell }^{2}}}{12}=2{{I}_{1}}\]. Now,  \[\frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{{{I}_{1}}}{{{I}_{2}}}}\]   or \[\frac{{{T}_{0}}}{{{T}_{2}}}=\sqrt{\frac{1}{2}}\] \[\therefore \,\,\,\,{{T}_{2}}=\sqrt{2}\,{{T}_{0}}\]


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