A) \[0.25\times {{10}^{-6}}\,T\]
B) \[0.36\times {{10}^{-6}}\,T\]
C) \[0.66\times {{10}^{-8}}\,T\]
D) \[1.2\times {{10}^{-6}}\,T\]
Correct Answer: B
Solution :
[b] \[{{T}_{1}}=\frac{60}{40}=1.5s\] and \[{{T}_{2}}=2.5\,s\] We know that, \[\frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{{{B}_{2}}}{{{B}_{1}}}}\] or \[{{B}_{2}}=\frac{T_{1}^{2}}{T_{2}^{2}}\times {{B}_{1}}={{\left( \frac{1.5}{2.5} \right)}^{2}}\times (0.1\times {{10}^{-5}})\] \[=0.36\times {{10}^{-6}}\,T\]
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