A) \[{{10}^{-2}}J\]
B) \[{{10}^{-4}}J\]
C) \[{{10}^{-6}}J\]
D) 0
Correct Answer: B
Solution :
[b] Loss in P.E. = gain in K.E. \[\therefore \,\,\,{{E}_{k}}={{U}_{i}}-{{U}_{j}}=-MB\,\cos \,{{90}^{o}}-(-MB\,cos\,{{0}^{o}})\] \[=4\times 25\times {{10}^{-6}}={{10}^{-4}}J\]
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