A) \[{{10}^{2}}\]
B) \[{{10}^{0}}\]
C) \[{{10}^{4}}\]
D) \[{{10}^{1}}\]
Correct Answer: C
Solution :
[c] \[\because \,\,\,{{\mu }_{r}}=\frac{\mu }{{{\mu }_{0}}}=\frac{B}{H{{\mu }_{0}}}\] or \[{{\mu }_{r}}\] \[=\frac{8\pi }{2\times {{10}^{3}}\times 4\pi \times {{10}^{-7}}}={{10}^{4}}\]
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