JEE Main & Advanced Physics Magnetism Question Bank Self Evaluation Test - Magnetism and Matter

  • question_answer
    A permanent magnet in the shape of a thin cylinder of length 10 cm has magnetisation (M) \[={{10}^{6}}\,A\,{{m}^{-1}}\]. Its magnetization current\[{{I}_{M}}\]is

    A) \[{{10}^{5}}\,A\]

    B) \[{{10}^{6}}\,A\]

    C) \[{{10}^{7}}\,A\]

    D) \[{{10}^{8}}\,A\]

    Correct Answer: A

    Solution :

    [a] As \[BI={{\mu }_{0}}M{{I}_{M}}={{\mu }_{0}}(I+{{I}_{M}})\] Here, \[I=0\] Then  \[{{\mu }_{0}}MI={{\mu }_{0}}({{I}_{M}})\Rightarrow {{I}_{M}}=MI={{10}^{6}}\times 0.1={{10}^{+5}}\,A\]


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