A) \[8.0\times {{10}^{2}}\,e.m.u.\]
B) \[1.2\times {{10}^{3}}\,e.m.u.\]
C) \[2.4\times {{10}^{3}}\,e.m.u.\]
D) \[3.6\times {{10}^{3}}\,e.m.u.\]
Correct Answer: B
Solution :
[b] \[B={{B}_{H}}\] or \[\frac{{{\mu }_{0}}}{4\pi }.\frac{2M}{{{r}^{3}}}=0.3\] \[\therefore \,\,\,\,\,M=1.2\times {{10}^{3}}\,emu\].You need to login to perform this action.
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