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JEE Main & Advanced Physics Magnetism Question Bank Self Evaluation Test - Magnetism and Matter

  • question_answer
    The mass of a speciment of a ferromagnetic material is 0.6 kg. and its density is \[7.8\times {{10}^{3}}\,kg/{{m}^{3}}\]. If the area of hysteresis loop of alternating magnetising field of frequency 50Hz is 0.722 MKS units then the   hysteresis loss per second will be                           

    A) \[277.7\times {{10}^{-5}}\,joule\]

    B) \[277.7\times {{10}^{-6}}\,joule\]

    C) \[277.7\times {{10}^{-4}}\,joule\]

    D) \[27.77\times {{10}^{-4}}\,joule\]

    Correct Answer: A

    Solution :

    [a] \[{{W}_{H}}=VA\,ft=\frac{m}{d}\,\,Aft\] \[=\frac{0.6}{7.8\times {{10}^{3}}}\times 0.722\times 50=277.7\times {{10}^{-5}}\,Joule\]


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