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JEE Main & Advanced Physics Magnetism Question Bank Self Evaluation Test - Magnetism and Matter

  • question_answer
    A bar magnet of magnetic moment \[3.0\,A-{{m}^{2}}\] is placed in a uniform magnetic field of \[2\times {{10}^{-5}}T\].If each pole of the magnet experiences a force of \[6\times {{10}^{-4}}N\], the length of the magnet is

    A) 0.5 m

    B) 0.3 m

    C)  0.2 m

    D) 0.1 m

    Correct Answer: D

    Solution :

    [d] \[F=mB\] or \[6\times {{10}^{-4}}=m\times 2\times {{10}^{-5}}\] \[\therefore \,\,\,\,m=30\,A-m\] Now,  \[\ell =\frac{M}{m}=\frac{3}{30}=0.1m\]


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