A) A tautology
B) A contradiction
C) Neither a tautology nor a contradiction
D) Cannot come to any conclusion
Correct Answer: C
Solution :
[c]| \[p\] | \[q\] | \[p\Rightarrow q\] | \[\tilde{\ }(p\Rightarrow q)\] | \[\tilde{\ }p\] | \[\tilde{\ }q\] | \[\tilde{\ }p\vee \tilde{\ }q\] | \[\tilde{\ }(p\Rightarrow q)\]\[\Leftrightarrow \tilde{\ }\]\[p\vee \tilde{\ }q\] |
| T | T | T | F | F | F | F | T |
| T | F | F | T | F | T | T | T |
| F | T | T | F | T | F | T | F |
| F | F | T | F | T | T | T | F |
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