JEE Main & Advanced Mathematics Determinants & Matrices Question Bank Self Evaluation Test - Matrices

  • question_answer
    sLet \[A=\left[ \begin{matrix}    1 & 2  \\    3 & 4  \\ \end{matrix} \right]\] and \[B=\left[ \begin{matrix}    a & 0  \\    0 & b  \\ \end{matrix} \right]\] where a, b are natural numbers, then which one of the following is correct?

    A) There exist more than one but finite number of B's such that AB = BA

    B) There exists exactly one B such that AB = BA

    C) There exist infinitely many B's such that AB=BA

    D) There cannot exist any B such that AB = BA

    Correct Answer: C

    Solution :

    [c] \[AB=\left[ \begin{matrix}    1 & 2  \\    3 & 4  \\ \end{matrix} \right]\left[ \begin{matrix}    a & 0  \\    0 & b  \\ \end{matrix} \right]=\left[ \begin{matrix}    a & 2b  \\    3a & 4b  \\ \end{matrix} \right]\] and \[BA=\left[ \begin{matrix}    a & 0  \\    0 & b  \\ \end{matrix} \right]\left[ \begin{matrix}    1 & 2  \\    3 & 4  \\ \end{matrix} \right]=\left[ \begin{matrix}    a & 2a  \\    3b & 4b  \\ \end{matrix} \right]\] If \[AB=BA\] \[\Rightarrow \left[ \begin{matrix}    a & 2b  \\    3a & 4b  \\ \end{matrix} \right]=\left[ \begin{matrix}    a & 2a  \\    3b & 4b  \\ \end{matrix} \right]\Rightarrow a=b\] From the above it is clear that there exist infinitely many B?s such that AB = BA.


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