A) I
B) \[{{S}^{2}}\]
C) S
D) O
Correct Answer: C
Solution :
[c] \[S=ABCD=A(BCD)=A{{A}^{T}}...(1)\] \[{{S}^{3}}=(ABCD)(ABCD)(ABCD)\] \[=(ABC)(DAB)(CDA)(BCD)\] \[={{D}^{T}}{{C}^{T}}{{B}^{T}}{{A}^{T}}\] \[={{(BCD)}^{T}}{{A}^{T}}=A{{A}^{T}}...(2)\] From (1) and (2), \[S={{S}^{3}}\]You need to login to perform this action.
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