A) \[\frac{1}{2}\]
B) \[\frac{1}{5}\]
C) No unique value of 'x'
D) None of these
Correct Answer: B
Solution :
[b] We have \[\left[ \begin{matrix} 2 & 0 & 7 \\ 0 & 1 & 0 \\ 1 & -2 & 1 \\ \end{matrix} \right]\] \[\left[ \begin{matrix} -x & 14x & 7x \\ 0 & 1 & 0 \\ x & -4x & -2x \\ \end{matrix} \right]=\left[ \begin{matrix} 5x & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 10x-2 & 5x \\ \end{matrix} \right]=\] \[\left[ \begin{matrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \\ \end{matrix} \right]\] \[\Rightarrow x=1/5\]
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