A) \[2\times {{10}^{5}}N/{{m}^{2}}\]
B) \[5\times {{10}^{4}}N/{{m}^{2}}\]
C) \[2\times {{10}^{7}}N/{{m}^{2}}\]
D) \[3\times {{10}^{6}}N/{{m}^{2}}\]
Correct Answer: A
Solution :
[a] Total cross-sectional area of the thigh bones \[A=2(10\times {{10}^{-4}})=2\times {{10}^{-3}}{{m}^{2}}\] Force acting on the bones \[=mg=40\times 10\]\[=400N\]b \[\therefore \,\,{{P}_{av}}=\frac{F}{A}=\frac{400}{2\times {{10}^{-3}}}=2\times {{10}^{5}}N/{{m}^{2}}\]
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