A) \[{{\rho }_{_{L}}}={{\rho }_{B}}\]
B) \[{{\rho }_{_{L}}}>{{\rho }_{B}}\]
C) \[{{\rho }_{_{L}}}<{{\rho }_{B}}\]
D) unpredictable
Correct Answer: B
Solution :
[b] As block B falls, L will decrease. Block B will displace, volume of liquid (\[{{V}_{1}}\]) Equal to its own volume when it is in the liquid. \[{{V}_{1}}={{V}_{B}}=\frac{{{M}_{B}}}{{{\rho }_{B}}}\] ...(i) When block B is on block A, it will displace the volume of liquid (\[{{V}_{2}}\]) whose weight is equal to the weight of the block B \[{{V}_{2}}{{\rho }_{L}}g={{M}_{B}}g=({{V}_{1}}{{\rho }_{B}})g\,\]or. Since H increases, \[{{V}_{1}}>{{V}_{2}}\] So, \[{{\rho }_{L}}>{{\rho }_{B}}\].
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