A) \[{{10}^{6}}N\]
B) \[5\times {{10}^{5}}N\]
C) \[25\times {{10}^{6}}N\]
D) \[5\times {{10}^{6}}N\]
Correct Answer: D
Solution :
[d] The pressure outside the submarine is \[P={{P}_{a}}+\rho gh\] Pressure inside the submarine is \[{{P}_{a}}\]. Net pressure acting on the window is \[{{P}_{g}}=P-{{P}_{a}}=\rho gh\] \[{{10}^{-3}}kg{{m}^{-3}}\times 10m{{s}^{-2}}\times 2000m\] \[=2\times {{10}^{7}}Pa\] Area of window is \[A=50cm\times 50cm=2500\times {{10}^{-4}}{{m}^{2}}\] Force on the window is \[F={{P}_{g}}A=2\times {{10}^{7}}Pa\times 2500\times {{10}^{-4}}{{m}^{2}}\] \[=5\times {{10}^{6}}N\]
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