A) 5 m/s
B) 30m/s
C) 35 m/s
D) None of these
Correct Answer: A
Solution :
[a] From the equation of continuity, Rate \[=r=\frac{A}{3}{{V}_{P}}+\left( A-\frac{A}{3} \right){{V}_{Q}}\] \[\therefore \,\,\,{{V}_{P}}+2{{V}_{Q}}=\frac{3r}{A}=\frac{3\times 0.1}{{{10}^{-2}}}=30m/s\] \[As\,\,{{V}_{p}}=20m/s,So\,\,{{V}_{Q}}=5m/s.\]You need to login to perform this action.
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