A) 0.3mm
B) 0.6mm
C) 0.9mm
D) 1.2mm
Correct Answer: B
Solution :
[b] Let the liquid rise to a height h. \[T=\frac{h\rho rg}{2}\] \[\therefore \,\,hr=\frac{2T}{\rho g}\] If the tube is of height \[{{h}_{1}}<h\] \[{{h}_{1}}{{r}_{1}}=hr=\frac{2T}{\rho g}\] \[\therefore \,\,\,\eta =\frac{2T}{{{h}_{1}}\rho g}=\frac{2\times 0.073}{\frac{25}{1000}\times 1000\times 9.8}\{25mm=\frac{25}{1000}m\}\]\[=\frac{2\times 0.073}{9.8\times 25}=0.0006m=0.6mm\]You need to login to perform this action.
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