A) \[\sqrt{\frac{2\gamma }{\rho g}}\]
B) \[\sqrt{\frac{\gamma }{\rho g}}\]
C) \[\frac{1}{2}\sqrt{\frac{\gamma }{\rho g}}\]
D) \[2\sqrt{\frac{\gamma }{\rho g}}\]
Correct Answer: A
Solution :
[a] Balancing forces in horizontal direction \[\left( {{p}_{0}}-\rho g\frac{h}{2} \right)\ell h=\gamma \ell ={{p}_{0}}\ell h\Rightarrow h=\sqrt{\frac{2\gamma }{\rho g}}\]You need to login to perform this action.
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