A) \[\frac{1}{2\sqrt{2}}\]
B) \[\frac{1}{2}\]
C) \[\frac{1}{4}\]
D) \[\frac{1}{\sqrt{2}}\]
Correct Answer: D
Solution :
[d] \[{{v}_{1}}=\sqrt{2}g(h/2).\] For \[{{v}_{2}}\] we can replace the liquid of density\[\rho \] and height h to a liquid of density \[2\rho \] and height\[h/2\] Thus \[{{v}_{2}}=\sqrt{2gh}=\sqrt{2v}\].You need to login to perform this action.
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