A) \[\frac{\eta k}{a}\]
B) \[\frac{\eta }{ka}\]
C) \[\frac{\eta a}{k}\]
D) None of these
Correct Answer: A
Solution :
[a] Newton's law of viscosity, \[F=\eta A\frac{dv}{dy}\] Stress\[=\frac{F}{A}=\eta \left( \frac{dv}{dy} \right)=\eta k\left( \frac{4y}{{{a}^{2}}}-\frac{3{{y}^{2}}}{{{a}^{3}}} \right)\] At\[y=a\], Stress\[=\eta k\left( \frac{4}{a}-\frac{3}{a} \right)=\frac{\eta k}{a}\]You need to login to perform this action.
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