A) 15 kg
B) 14 kg
C) 10 kg
D) 12 kg
Correct Answer: D
Solution :
[d] Weight of submerged part of the block \[W=\frac{1}{3}v\] (Density of water) g ...(i) Excess weight,=weight of water having \[\frac{2}{3}\]volume of the block. \[W'=\frac{2}{3}v\] (Density of water) g ...(ii) \[Dividing(ii)by(i),\,\,\frac{W'}{W}=\frac{2/3}{1/3}\] \[\therefore \,\,\,W'=2\Rightarrow W'=2\times 6=12kg\]You need to login to perform this action.
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