A) \[3.28c{{m}^{2}}\]
B) \[2.28c{{m}^{2}}\]
C) \[0.328c{{m}^{2}}\]
D) \[0.823c{{m}^{2}}\]
Correct Answer: A
Solution :
[a] Given, the breaking strength of cable \[{{f}_{u}}=7\times {{10}^{7}}N/{{m}^{2}}\] The force carried by the cable, \[F=m(g+a)=2000(9.8+1.5)22600N\] The area of cross-section, \[A=\frac{F}{{{f}_{u}}}=\frac{22600}{7\times {{10}^{7}}}\] \[=3.28\times {{10}^{-4}}{{m}^{2}}\]You need to login to perform this action.
You will be redirected in
3 sec